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Beta Spectroscopy Experiment



 Abstract

In this experiment we will study the process of beta decay, measurements of the shape of beta ray spectrum and determination of beta spectrum end-point energy by graph a kurie or Fermi plot. Also, we will calculate the resolution of the spectrometer by using the internal conversion peaks.

Introduction

The three common decay modes of nuclei (α, β, and γ) were all observed by the early twentieth century. When a nucleus decays, all the conservation laws must be observed: mass-energy, linear momentum, angular momentum, and electric charge. To these laws we add another one for radioactive decay, called the conservation of nucleons. It states that the total number of nucleons (A, the mass number) must be conserved in a low-energy nuclear reaction (say, less than 938 MeV) or decay. Neutrons may be converted into protons, and vice versa, but the total number of nucleons must remain constant.

Radioactive decay may occur for a nucleus when some other combination of the A nucleons has a lower mass. Let the radioactive nucleus A Xbe called the parent and have the mass M (A Z). Two or more products can be produced in the decay. The study of Beta decay as well as Alpha and Gamma signaled the start of the nuclear physics and led to the prediction of the existence of the neutrino.

Radioactive decay occurs because some nuclides are not stable. In Figure1 we showed a plot of stable nuclei. In many cases alpha decay leaves the daughter nucleus farther from the line of stability than the parent. Unstable nuclei may move closer to the line of stability by undergoing beta decay. The simplest example of beta decay is the decay of a free neutron.


n   →   P + β-



Figure 1: A plot of the known nuclides with neutron number N versus proton number Z. The solid points represent stable nuclides, and the shaded area represents unstable nuclei. A smooth line through the solid points would represent the line of stability.

The decay produces two products and we expect to measure a monoenergetic electron spectrum. However, the electron energy spectrum from the beta decay (see Figure 2) shows a continuous energy spectrum up to a maximum energy. This experimental result was a major puzzle for many years. In addition to the strange energy spectrum, there was a problem with spin conservation. In neutron decay, the spin 1/2 neutron cannot decay to two spin 1/2 particles, a proton and an electron. We cannot combine spin 1/2 and 1 to obtain a spin of 0. Both the electron energy spectrum and the spin angular momentum conservation posed major difficulties with our understanding of beta decay.
The correct explanation was proposed in 1930 by Wolfgang Pauli, who suggested that a third particle—later called a neutrino—must also be produced in beta decay. The neutrino, with the symbol ν , has spin quantum number 1/2, charge 0, and carries away the additional energy missing in Figure 2. In Figure 2 an occasional electron is detected with the kinetic energy K max required to conserve energy, but in the great majority of cases the electron’s kinetic energy is less than K max. We know that the  neutrino has mass, although it is extremely small. Its energy is almost all kinetic.
The photon cannot be the missing particle because it has spin 1. Pauli’s suggestion seemed to explain the difficulties, and all circumstantial evidence supported the neutrino hypothesis. However, the detection of the elusive neutrino was difficult, and its existence was not proven experimentally until 1956 by C. 



In order to incorporate these features, Fermi formulated a field theory for β decay. The Fermi theory assumes that the β decay of a nucleus proceeds via the β decay of one of the nucleons making up the nucleus. It thus predicted the following basic nuclear β decay processes:










In this experiment the beta ray spectrometer utilizes a magnetic field (B) which deflects the 

particles in a path of known curvature through an angle 1800 between two points (the source and the detector) spaced at a distance 2r apart. The 1800 point on the trajectory is called the "first order focus" because electrons emitted with small angular deviations from normal tend to be focused at 1800.

For most of the beta-decay particles, relativistic relations connecting the momentum and kinetic energy must be used in the calculations, i.e.

Thus if the rest mass of the particle is known, its energy can be deduced from the measured momentum using the spectrometer. An electron with velocity v entering a region where there is a magnetic field B , such that v is perpendicular to  B suffers a magnetic force:

FM = evB = (mv^2) / r

P = mv = eBr

Combining this equations we get:



The spectrum of 𝜷 decay is continuous, so it cannot be used to calibrate the energy measurements taken by the spectrometer with good precision. Some beta sources produce a mono-energetic spectral line in addition to the continuous beta spectrum. These mono-energetic electrons are due to a transition process known as internal conversion.

The internal conversion arises when one or more nucleons in the nucleus rearrange themselves during a transition from an initial to a final state. The nuclear energy (Ei - Ef) is transferred directly to an atomic electron bound in the atom with an energy Ex where x is the atomic shell (K, L, M, … etc.) or emits γ-radiations, because these processes are independent. Fig. 3 shows the spectrum of 137Cs which consists of a continuous spectrum and a spectral line. Note the continuous part (due to beta decay) and the monoenergetic lines (due to "internal conversion" resulting in the ejection of an electron from the K and L shells). Usually the spectrometer is calibrated and its resolution is measured by the study of the internal conversion electron spectra. The conversion electron energies Ee for K and L shell of 137Cs are 624.2 keV and 656.0 keV [3], respectively




Methodology



Apparatus:

1. Beta ray source 137Cs.

2. End window Geiger counter.

3. Scaler to count the emitted beta particles.

4. Rotary vacuum pump to evacuate the chamber housing the source and the counter.

5. Electromagnet with its power supply.



Procedure:

1. Use the rotary pump to evacuate the vacuum chamber in order to reduce the collisions between the b particles and the air molecules.

2. Be sure that the end window Geiger counter is operated within its plateau region. Higher voltages will damage the counter. Note: Do not exceed 500 volts on the Geiger counter used in this experiment.

3. With no magnet current flowing, take the background counting rate for a period of at least 15 minutes.

4. Raise the magnet current gradually and take the number of the counts per 3 minutes N(p) for different values of the magnetic fields B (or the magnet current I).

5. Make sure that you continue increasing the magnet current until you obtain a broad peak and a sharp peak.



Data Analysis

Calculate Pe and Ee for each value of the magnetic field B.

the background value corresponds to I=0  the table below shows the corrected count rate number which is the counts number taken every 300 sec – the background value .

to calculate the value of B  use this equation

B(mT) = -23.88I^2 + 19.54I^2 + 147I + 1.253

To convert it to Gauss use the relation:

1Gauss=10^-4

R=1.5inch=3.81cm

current(A)

N/300sec

N

B (GAUSS)

B*r(Gauss.cm)

0

120

0

12.53

47.7393

0.02

172

52

42.00625

160.0438125

0.04

149

29

71.62736

272.9002416

0.06

166

46

101.62736

387.2002416

0.08

168

48

131.2583

500.094123

0.1

195

75

161.2452

614.344212

0.12

264

144

191.3311

728.971491

0.14

345

225

221.5046

843.932526

0.16

338

218

251.7541

959.183121

0.18

388

268

282.0683

1074.680223

0.2

425

305

312.4356

1190.379636

0.22

444

324

342.8446

1306.237926

0.24

458

338

373.2839

1422.211659

0.26

480

360

403.7419

1538.256639

0.28

417

297

434.2072

1654.329432

0.3

450

330

464.6684

1770.386604

0.32

429

309

495.114

1886.38434

0.34

403

283

525.5324

2002.278444

0.36

403

283

555.9124

2118.026244

0.38

360

240

586.2423

2233.583163

0.4

324

204

616.5108

2348.906148

0.42

342

222

646.7063

2463.951003

0.44

292

172

676.8175

2578.674675

0.46

239

119

706.8328

2693.032968

0.48

191

71

736.7408

2806.982448

0.5

170

50

766.53

2920.4793

0.51

173

53

781.3765

2977.044465

0.52

160

40

796.189

3033.48009

0.53

129

9

810.966

3089.78046

0.54

175

55

825.7062

3145.940622

0.55

199

79

840.4082

3201.955242

0.56

389

269

855.0703

3257.817843

0.57

461

341

869.6914

3313.524234

0.58

541

421

884.2698

3369.067938

0.59

512

392

898.8042

3424.444002

0.6

449

329

913.2932

3479.647092

0.61

331

211

927.7353

3534.671493

0.62

178

58

942.129

3589.51149

0.63

163

53

956.373

3643.78113

0.64

155

35

970.7695

3698.631795

0.65

136

16

985.0061

3752.873241

0.66

141

21

1232.1227

4694.387487




























































This graph represents the beta spectrum , it's a continuous spectrum with two monochromatic energy  lines ,k and L shells resulting from internal conversion electrons. The first peak corresponding to k shell electrons occurred at current 0.58 A , the second peak corresponding to L-shell electrons occurred at 0.60 A .

N

P

Ee(Mev)

T(Mev)

p^2

(n/p^2)^1/2

0

0.014319

0.511201

0

0.000205

0

52

0.048004

0.51325

0.00225

0.002304

150.231

29

0.081854

0.517514

0.006514

0.0067

65.79025

46

0.115856

0.523969

0.012969

0.013423

58.54018

48

0.149998

0.53256

0.02156

0.022499

46.18904

75

0.184266

0.543208

0.032208

0.033954

46.9986

144

0.218648

0.555813

0.044813

0.047807

54.8827

225

0.253129

0.570259

0.059259

0.064074

59.2584

218

0.287697

0.586422

0.075422

0.08277

51.3206

268

0.32234

0.604172

0.093172

0.103903

50.78709

305

0.357042

0.623378

0.112378

0.127479

154.6787

324

0.391793

0.643912

0.132912

0.153502

45.9425

338

0.426578

0.66565

0.15465

0.181969

43.0982

360

0.461385

0.688474

0.177474

0.212876

41.1232

297

0.4962

0.712275

0.201275

0.246214

34.7313

330

0.53101

0.724508

0.213508

0.281972

34.21007

309

0.565802

0.736948

0.225938

0.320132

31.0681

283

0.600563

0.7624

0.2514

0.360676

28.0113

283

0.635281

0.788541

0.277541

0.403582

26.4805

240

0.669941

0.815293

0.304293

0.448821

23.1243

204

0.704531

0.842581

0.331581

0.496364

20.2728

222

0.739038

0.88437

0.37337

0.546177

20.1608

172

0.773448

0.912712

0.401712

0.598222

16.9563

119

0.807784

0.941376

0.430376

0.652515

13.5044

71

0.841926

0.970311

0.459311

0.708839

10.0081

50

0.875969

0.999471

0.488471

0.767322

8.0722

53

0.892935

1.014121

0.503121

0.797333

8.153

40

0.909862

1.028812

0.517812

0.827849

6.9511

9

0.926749

1.043537

0.532537

0.858864

3.2371

55

0.943594

1.058293

0.547293

0.89037

7.8595

79

0.960394

1.073075

0.562075

0.922357

9.2547

269

0.97715

1.087878

0.576878

0.954822

16.7847

341

0.993858

1.102698

0.591698

0.987754

18.5803

421

1.010518

1.117531

0.606531

1.021147

20.3047

392

1.027128

1.132373

0.621373

1.054992

19.276

329

1.043685

1.147219

0.636219

1.089278

17.3791

211

1.060185

1.162067

0.651067

1.123992

13.7012

58

1.076638

1.176912

0.665912

1.159149

7.0736

53

1.09303

1.191751

0.680751

1.194715

6.6604

35

1.109363

1.20658

0.69558

1.230686

5.3328

16

1.125637

1.221396

0.710396

1.267059

3.5535


Figure 2: Kurie plot to determine the end point energy (max. energy of beta particle ).

End point energy = x-intercept = 108.22 / 89.807 = 1.205 MeV

T0 =Etotal-0.511=0.694 Mev

Accepted value of T0 =0.514             Mev 







To estimate the true value our slope and y-intercept we use the least square method:

Ee(Mev)

(n/p^2)^1/2

x*y

x^2

(y-a-bx)^2

0.511201

0

0

0.261326

3882.607

0.51325

150.231

77.10606

0.263426

7762.393

0.517514

65.79025

34.04738

0.267821

16.37521

0.523969

58.54018

30.67324

0.274544

6.883991

0.53256

46.18904

24.59844

0.28362

201.735

0.543208

46.9986

25.53002

0.295075

154.6919

0.555813

54.8827

30.50452

0.308928

11.70599

0.570259

59.2584

33.79264

0.325195

5.069928

0.586422

51.3206

30.09553

0.343891

17.93183

0.604172

50.78709

30.68414

0.365024

10.0745

0.623378

154.6787

96.4233

0.3886

10494.45

0.643912

45.9425

29.58293

0.414623

19.79979

0.66565

43.0982

28.68832

0.44309

28.53451

0.688474

41.1232

28.31225

0.473996

27.74145

0.712275

34.7313

24.73824

0.507336

90.65742

0.724508

34.21007

24.78547

0.524912

79.99585

0.736948

31.0681

22.89557

0.543092

120.3148

0.7624

28.0113

21.35582

0.581254

137.8239

0.788541

26.4805

20.88096

0.621797

119.3119

0.815293

23.1243

18.85308

0.664703

141.0556

0.842581

20.2728

17.08148

0.709943

150.7377

0.88437

20.1608

17.82961

0.78211

74.59057

0.912712

16.9563

15.47622

0.833043

86.4114

0.941376

13.5044

12.71272

0.886189

103.499

0.970311

10.0081

9.71097

0.941503

122.571

0.999471

8.0722

8.06793

0.998942

107.9169

1.014121

8.153

8.268129

1.028441

80.8531

1.028812

6.9511

7.151375

1.058454

78.75463

1.043537

3.2371

3.378034

1.088969

126.9221

1.058293

7.8595

8.317654

1.119984

28.28517

1.073075

9.2547

9.930987

1.15149

6.737417

1.087878

16.7847

18.25971

1.183479

39.23468

1.102698

18.5803

20.48846

1.215943

88.17772

1.117531

20.3047

22.69113

1.248876

154.923

1.132373

19.276

21.82762

1.282269

162.5886

1.147219

17.3791

19.93763

1.316111

148.5326

1.162067

13.7012

15.92171

1.3504

96.88369

1.176912

7.0736

8.325005

1.385122

20.68918

1.191751

6.6604

7.937538

1.42027

29.89883

1.20658

5.3328

6.43445

1.455835

29.94421

1.221396

3.5535

4.340231

1.491808

25.23465

sum

34.93481

1299.542

897.6365

32.10143

25092.54




a is the intercept and b is the slope .














The error in a and b using these equations:























For resolution computations and from internal conversion spectrum :

I A

 N/I(1/A)

0.53

243.3962

0.54

324.0741

0.55

361.8182

0.56

694.6429

0.57

808.7719

0.58

932.7586

0.59

867.7966

0.6

748.3333

0.61

542.623

0.62

287.0968

0.63

258.7302

0.64

242.1875



From the graph we can obtain the following information :

(N / Imax)  = 932.75 (1  /A)

Imax = 0.58 A

Height = (1/2)(N/Imax) = 659.5538 (1/A)

 The half max.=329.7769(1/A) 

∆I at half max. value =(0.62-0.54)= 0.08A 

R = ∆I/I =0.1379


Conclusion

* The beta particles are high energy, high speed electrons or positrons that are ejected from nucleus by some radio nuclei.

* Normally beta decay occurs in nuclei that have too many neutrons to achieve stability. 

*We calculated the kinetic energy of electrons with percentage error= 35.01 %

* We calculated the resolution of the spectrometer and obtained R=0.1379.



References

1- Arthur Beiser; Concepts of Modern Physics, Sixth Edition.

2- Manual of the advanced practical physics 5.

3- Modern Physics, For Scientists and Engineers, Fourth Edition, Stephen T. Thornton.

4- https://wanda.fiu.edu/boeglinw/courses/Modern_lab_manual3/_images/Sr90_decay.png

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